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Martingale simulator

Doubling after a loss feels safe because one paying bet recovers every loss before it. The catch is the losing streak that empties the bankroll first. Run it 1,000 times and count.

Simulator

Pick a starting point or enter your own numbers. The bet doubles after every loss and returns to the base bet after every paying bet.

Starting point

Pays 49.5% of the time, at even money.

Between 0 and 100.

When a bet pays. 1 is even money; a 2.00x cash-out pays 1.

The bet after every paying bet.

A session goes bust when the next doubled bet is more than what is left.

Up to 10,000.

Simulation, not advice.

1,000 simulated sessions

Sessions that went bust

64.3%

643 of 1,000 sessions could not place the next doubled bet within 200 rounds.

Ended above the starting bankroll
357 of 1,000
Average bankroll at the end
98.16 (from 100)
Largest single bet
64
Losing streak that ends a fresh session
6 in a row
Chance that 6 given bets all lose
1.66%
Average return per bet
−1.0%

Sessions are seeded 1 to 1,000, so the same inputs always give the same result.

How the simulation works

Each session starts with the bankroll and the base bet. After a losing bet the next bet doubles; after a paying bet it returns to the base bet. A session goes bust when the next bet is more than what is left, and otherwise stops after the set number of rounds.

Each bet has two outcomes, with the chance and payout you set. Bets with several payout levels are not modelled here.

Doubling changes how losses arrive, not their average size. Every bet keeps the same average return, so the session keeps it too: many small gains, paid for by rare large losses.

A bankroll B with base bet b pays for k losses in a row, the largest k with b × (2^k − 1) ≤ B. After those k losses the next bet cannot be placed. The chance that k given bets all lose is (1 − p)^k, where p is the chance a bet pays.

The belief

Doubling after a loss is one of the four myths the lab checks.

Read the myth check: does doubling after a loss work?